A combination of variables, numerals (numbers), and operation signs to represent a value.
Example: $5a + 6b - 2$
A symbol (usually a letter) representing an unknown value.
Let $a =$ your age.
The distance of a number from zero on a number line. It is always non-negative.
$|-3| = 3$ and $|-0.75| = 0.75$
Nested subsets of the real numbers:
$a + b = b + a$, $ab = ba$
$(a + b) + c = a + (b + c)$, $(ab)c = a(bc)$
$7(x - y) = 7x - 7y$
$-5(x - 3y + 2z) = -5x + 15y - 10z$
$a + 0 = a$ and $a \cdot 1 = a$
$\frac{0}{a} = 0$ (for $a \neq 0$) and $\frac{a}{0}$ is undefined
$12 + (-9) = 3$ (Since 12 is larger than 9, the answer is positive)
$-8 + 5 = -3$ (Since 8 is larger than 5, the answer is negative)
$3 - 7 = 3 + (-7) = -4$
$-4 - (-10) = -4 + 10 = 6$
$5(3+4) - \{8 - [5 - (9+6)]\} = 17$
"Six more than some number" translates to $x + 6$
"Five less than the product of two numbers" translates to $xy - 5$
A replacement for the variable that makes the equation true.
For $x + 12 = 21$, if we replace $x$ with $9$, it is true.
A number sentence containing $>$, $<$, $\geq$, or $\leq$.
$x < 3$ (Numbers less than 3)
Vocabulary cues for operations:
Solve $y - 17.9 = -8.3$ by adding $17.9$ to both sides
Solve $-7x = 84$ by dividing both sides by $-7$
$4x + 7 - 6x = 10 + 3x + 12$ simplifies to $-2x + 7 = 3x + 22$
Solving yields $x = -3$
$-4y < 20$ becomes $y > -5$ (Dividing by $-4$ reverses $<$ to $>$)
"Brian is at least 16" $\Rightarrow b \geq 16$
"At most 3 students failed" $\Rightarrow s \leq 3$
$6x - 15 = 3(2x - 5) \Rightarrow 0 = 0$ (infinite solutions)
$2x + 5 = 2x - 15 \Rightarrow 5 = -15$ (no solution)
Solve $C = \pi d$ for $d$. Result: $d = \frac{C}{\pi}$
"What is 25% of 60?" translates to $a = 0.25 \cdot 60$
The four regions of the coordinate plane, numbered counterclockwise starting from the upper right:
Note: Points on the x-axis or y-axis are not in any quadrant.
Point $(-4, 5)$ is in Quadrant II
Point $(3, 0)$ is on the x-axis (not in a quadrant)
An equation whose graph is a straight line.
Example: $y = 3x$
Where the line crosses the axes.
For $5x + 2y = 10$, if $x=0$, $2y=10 \rightarrow y=5$
Point: $(0, 5)$
For $5x + 2y = 10$, if $y=0$, $5x=10 \rightarrow x=2$
Point: $(2, 0)$
The ratio of vertical change to horizontal change.
For points $(-4, 5)$ and $(4, -1)$:
Slope $m = \frac{-1 - 5}{4 - (-4)} = \frac{-6}{8} = -\frac{3}{4}$
Equation $y = b$. The slope is 0.
$y = 2$ is a horizontal line passing through $(0, 2)$
Equation $x = a$. The slope is undefined.
$x = -2$ is a vertical line passing through $(-2, 0)$
A monomial or sum/difference of monomials.
Example: $5x^4 - 8x^2y + y - 9$
Permit only whole-number exponents, no variables in denominators or radicals, and real-number coefficients.
Valid Polynomials:
NOT Polynomials (Common Mistakes):
Classified by term count:
Standard form lists terms in descending exponent order; ascending order reverses that.
Standard Form (Descending):
$5x^4 - 3x^3 + 7x^2 - 2x + 9$
Ascending Form:
$9 - 2x + 7x^2 - 3x^3 + 5x^4$
Common Mistake:
Writing $3x + 7x^3 - 2x^2 + 5$ (not in order)
The highest degree of any of its terms.
In $4x^2 - 9x^3 + 6x^4 + 8x - 7$, the highest exponent is 4, so the degree is 4.
Tricky Examples:
Writing numbers as $M \times 10^n$.
$0.000567 = 5.67 \times 10^{-4}$
$a^m \cdot a^n = a^{m+n}$
$m^5 \cdot m^2 = m^{5+2} = m^7$
$\frac{m^5}{m^2} = m^{5-2} = m^3$
$(y^6)^{-3} = y^{-18}$
$a^0 = 1$ (for $a \neq 0$) and $a^{-n} = \frac{1}{a^n}$
$(-5)^0 = 1$ and $3^{-4} = \frac{1}{81}$
Scientific Notation Constraint: The coefficient $M$ must satisfy $1 \leq M < 10$
$6.8 \times 10^5$ for 680000
$(-6x^3 + 7x - 2) + (5x^3 + 4x^2 + 3) = -x^3 + 4x^2 + 7x + 1$
$(21a^5b^4 - 14a^3b^2 + 7a^2b) \div (-7a^2b) = -3a^3b^3 + 2ab - 1$
$(x + 4)(x^2 + 3) = x^3 + 3x + 4x^2 + 12$
$(A+B)(A-B) = A^2 - B^2$
$(x + 8)(x - 8) = x^2 - 64$
$(A+B)^2 = A^2 + 2AB + B^2$
$(x + 8)^2 = x^2 + 16x + 64$
If $x^2 + y^2 = 20$ and $xy = 10$, then $(x + y)^2 = 40$
Proof: $(x + y)^2 = x^2 + 2xy + y^2 = (x^2 + y^2) + 2xy = 20 + 2(10) = 40$
The largest factor common to all terms.
For $30x^3, -48x^4, 54x^5, 12x^2$, the GCF is $6x^2$
A polynomial that cannot be factored further.
$x^2 - x + 7$
Start by diagnosing the expression: look for a GCF first, then choose a method based on term count (two terms → special products, three terms → trinomial methods, four or more → grouping or hybrids).
Always the first step.
$28x^6 + 32x^3 = 4x^3(7x^3 + 8)$
Group terms, factor GCF from each group, then factor the common binomial.
$3x^3 + 9x^2 + x + 3 = 3x^2(x+3) + 1(x+3) = (3x^2+1)(x+3)$
$A^2 - B^2 = (A+B)(A-B)$
$x^2 - 9 = (x+3)(x-3)$
Sum of Squares Reminder: $A^2 + B^2$ is prime over the reals
$16x^2 + 25$ (prime)
Find two numbers that multiply to $c$ and add to $b$.
$y^2 - 8y + 15$
Factors of 15 that add to -8 are -3 and -5
Result: $(y-3)(y-5)$
Multiply $a \cdot c$, find factors of $ac$ that add to $b$, split the middle term.
$4x^2 - 5x - 6$
Multiply $4(-6) = -24$
Factors of -24 adding to -5 are -8 and 3
Split: $4x^2 - 8x + 3x - 6$, then group to solve
If $(x-a)(x-b) = 0$, then $x=a$ or $x=b$.
$(x+4)(x-3) = 0 \Rightarrow x = -4$ or $x = 3$
First and last terms are squares and the middle term is twice their product, so factor to a binomial square.
$25x^2 - 20x + 4 = (5x - 2)^2$
1. GCF? → Factor it out first (ALWAYS!)
2. Count terms:
3. Equation? → Factor, then solve
Difference of Squares
$9x^2 - 25 = (3x + 5)(3x - 5)$
1: Perfect Square Trinomial
$4x^2 + 20x + 25 = (2x + 5)^2$
2: Simple Trinomial (a = 1)
$x^2 + 7x + 12 = (x + 3)(x + 4)$
3: AC Method (a ≠ 1)
Example: $3x^2 + 10x + 8$
Values that make the denominator zero.
In $\frac{x+3}{x^2 - 3x - 28}$, the denominator factors to $(x-7)(x+4)$
Excluded values are $7$ and $-4$
Factor numerator and denominator, then cancel common factors.
$\frac{3x - 12}{5x - 20} = \frac{3(x-4)}{5(x-4)} = \frac{3}{5}$
Multiply straight across.
$\frac{x^2 + 5x + 4}{x^2 - 9} \cdot \frac{x - 3}{x + 4}$ (After factoring and canceling, this simplifies)
Multiply by the reciprocal.
$\frac{x}{9} \div \frac{8}{y} = \frac{x}{9} \cdot \frac{y}{8} = \frac{xy}{72}$
Must have a common denominator (LCD).
$\frac{4x}{x-7} + \frac{3x+2}{x-7} = \frac{7x+2}{x-7}$
Multiply the whole equation by the LCD to clear fractions.
$\frac{x}{5} = \frac{x}{2} - \frac{1}{4}$
Multiply by 20: $4x = 10x - 5$
Cross-multiply to solve $\frac{A}{B} = \frac{C}{D}$.
$\frac{x-2}{x-3} = \frac{x-1}{x+1}$
$(x-2)(x+1) = (x-1)(x-3)$ leading to $x = \frac{5}{3}$
A relationship where each input (domain) has exactly one output (range).
Domain $\{-5, 1, 3, 4\}$, Range $\{1, 0, -5, 3\}$ from graph points
Relations can map one input to multiple outputs, but functions cannot.
Domain $\{9\}$ mapping to range $\{-3, 3\}$ is a relation, not a function
If a vertical line touches the graph more than once, it is not a function.
A sideways parabola is not a function because a vertical line crosses it twice
$f(x) = \frac{3x}{x-4}$ has domain $\{x | x \neq 4\}$
$y = mx + b$
$f(x) = -3.1x + 7$
Slope $m = -3.1$, y-intercept is $(0, 7)$
$y - y_1 = m(x - x_1)$
Line with slope 3 through $(2, 7)$ becomes $y - 7 = 3(x - 2)$
Simplifying to $y = 3x + 1$
Have the same slope.
$y = -2x - 3$ is parallel to $8x + 4y = -6$
(which simplifies to $y = -2x - 1.5$)
Both slopes are -2
Slopes are negative reciprocals (product is -1).
$y = 4x + 1$ is perpendicular to $x + 4y = 4$ (slope $-1/4$)
Find the intersection point of two lines.
Graphing $y = 3x + 1$ and $x - 2y = 3$ reveals the intersection point $(-1, -2)$
Solve one equation for a variable and plug it into the other.
System: $x = 3 - y$ and $5x + 3y = 5$
Substitute $(3-y)$ for $x$ in the second equation:
$5(3-y) + 3y = 5$
Add equations to eliminate a variable.
$4x + 3y = 8$
$x - 3y = 7$
Adding these gives $5x = 15$, so $x = 3$
Lines are parallel (No solution).
$y = \frac{3}{4}x + 2$ and $y = \frac{3}{4}x - 3$
Lines are identical (Infinite solutions).
$4x + 8y = 16$ and $2x + 4y = 8$
Has at least one solution (lines intersect).
Represent distinct lines.
Elements common to both sets ("AND").
Intersection of $\{a, b, c, d, e\}$ and $\{a, e, i, o, u\}$ is $\{a, e\}$
Elements in either set ("OR").
Union of the sets above is $\{a, b, c, d, e, i, o, u\}$
$6 < 2x - 4 < 10$
Add 4 to all parts: $10 < 2x < 14$
Divide by 2: $5 < x < 7$
$|X| = p$ means $X = p$ or $X = -p$.
$|x| = 7 \Rightarrow x = 7$ or $x = -7$
$|2x + 1| = 5 \Rightarrow 2x+1=5$ or $2x+1=-5$
$|x| < 3 \Rightarrow -3 < x < 3$
$|x| \geq 3 \Rightarrow x \geq 3$ or $x \leq -3$
Key Rules:
Example 1: To graph $y < \frac{1}{2}x - 1$:
Example 2: To graph $y \geq 2x + 3$:
Note: Points on the solid line are part of the solution!